Q:

The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the function h(t)=300-16t2. Which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall.

Accepted Solution

A:
your average speed is the average difference over time (in this case 3 seconds)

[tex] \frac{h(3)-h(0)}{3}=\\ \frac{300-16*3^2-(300-16*0^2)}{3}=\\ \frac{300-16*3^2-(300)}{3}=\\ \frac{-16*3^2}{3}=\\ -16*3=-48[/tex]